A wheel of radius R rolls on the ground with a uniform velocity v. The relative acceleration of topmost point of the wheel with respect to the bottommost point is:

Options

A. `(v^(2))/R`
B. `(2v^(2))/R`
C. `(v^(2))/(2R)`
D. `(4v^(2))/R`

Answer

2

Explanation

`omega=v/R, a =omega^(2) r =(v/R)^(2) .2R=(2v^(2))/R`