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A particle performing uniform circular motion gas angular momentum `L`. If its angular frequency is double and its kinetic energy halved, then the new angular momentum is :

A

2L

B

4L

C

L/2

D

L/4

Text Solution

Verified by Experts

The correct Answer is:
4

`(I_(1)omega_(1))/(I_(2)omega_(2))=(L_(1))/(L_(2))`
`omega_(2)=2omega_(1)`
`1/2 I_(2)omega_(2)^(2)=1/2(1/2I_(1)omega_(1)^(2))`
`rArr I_(2)=(I_(1))/8`
`rArr L_(2)=(L_(1))/4`
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