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A man generates a symmetrical pulse in a...

A man generates a symmetrical pulse in a string by moving his hand up and down. At t = 0, the point in his hand moves downwards from mean position. The pulse travels with speed `3m//s` on the string and his hand passes 6 times in each second from the mean position. Then, the point on the string at a distance 3 m will reach its upper extreme first time at t =

A

1.25 sec

B

1 sec

C

`13/12` sec

D

none

Text Solution

Verified by Experts

The correct Answer is:
A or C or D

`f=3 Hz " " rArr T=1/3 sec`
`lambda=1m`
His hand at upper extreme at `(3T)/4=1/4` sec
This message reaches x=3 at t=1 sec. later.
`rArr 1.25 sec`
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