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A solution of substance containing 1.05 ...

A solution of substance containing `1.05` g per 100 mL was found to be isotonic with `3%` glucose solution . The molecular mass of the substance is :

A

31.54

B

6.3 u

C

630 u

D

63 u

Text Solution

Verified by Experts

The correct Answer is:
D
`pi_(x)=pi_("glucose")`
`iC_(x)RT=iC_("glucose")RT`
`C_(x)=C_("glucose")`
`(1.05)/(MM)xx(1000)/(100)=(3g)/(180)xx(1000)/(100)`
`MM=63`
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