If solutbility of `CH_(3)` COOAg(s) in a buffer solution of pH equal to 5 is `1.414 xx10^(-y)` then calculate the value of y.
Given : `K_(sp)(CH_(3)COOAg)=10^(-10),K_(a)(CH_(3)COOH)=10^(-5)`

Answer

5

Explanation

`CH_(3)COOAg(s)iffCH_(3)COO^(-)(aq)+Ag^(+)(aq)`
`CH_(3)COO^(-)(aq)+H_(2)O iff CH_(3)COOH+OH^(-)`
`{:(x-z,,,,,,,,z,,,10^(-9)):}`
`K_(h)=(10^(-14))/(10^(-5))=(zxx10^(-9))/(x-z)" "," "x-z=zimplies z=(x)/(2)`
`K_(sp)=10^(-10)=(x-z)xx x" ",10^(-10)=(x)/(2)xx x`
Solubility `x=sqrt(2)xx10^(-5)`
Solubility `x=1.414xx10^(-y)`
y=5