Calculate equivalent conductivity at infinite dilution of the salt KOOC-COONa. Given the ionic molar conductivities at infinite dilution are:
`lambda^(oo)(C_(2)O_(4)^(2-))=148.5S cm^(2)mol^(-1)`,
`lambda^(oo)(K^(+))=50.1 S cm^(2) mol^(-1)`
`lambda^(oo)(Na^(+))=73.5 S cm^(2) mol^(-1)`
and

Options

A. `136.05 S cm^(2)eq^(-1)`
B. `544.2 Scm^(2) eq^(-1)`
C. `272.1 S cm^(2) eq^(-1)`
D. `27.21 S cm^(2) eq^(-1)`

Answer

D

Explanation

Number of faraday `(q_(F))=(9.65xx60xx1.5)/(96500)=9xx10^(-3)F`
`2e^(-)+Cu^(+2)rarrCu`
`" "(9xx10^(-3))/(2)xx64=0.288`
`4OH^(-)rarrO_(2)+2H_(2)O+4e^(-)`
`" "(9xx10^(-3))/(4)xx32=0.072g`
Total wt. loss `=0.288+0.072=0.360g`