x g of glucose was dissolved in 500 g wa...

x g of glucose was dissolved in 500 g water and cooled upto `-0.25^(@)C`, due to which 128 g of ice is seperated out from the solution. Then the value of x is `("Given" : K_(f)(H_(2)O)=1.86K.kg "mol"^(-1))`

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x g of urea was dissolved in 500 g of water and cooled upto -0.5^(@)C whereby 128 g of ice separates out from the solution. If cryoscopic constant for water be 1.86^(@)C//m . Calculate the value of x .

1000gm of sucrose solution in water is cooled to -0.5^(@)C . How much of ice would be separated out at this temperature, if the solution started to freeze at -0.38^(@)C . Express your answer in gram. (K_(f)H_(2)O=1.86K "mol"^(-1)kg)

A 10 m solution of urea is cooled to -13.02^(@)C . What amount of urea will separate out if the mass of solution taken is 100 g ? [K_(f)("water") =1.86 Kkg mol^(-1)]

When a solution w g of urea in 1 Kg of water is cooled to -0.372^(@)C,200g of ice is separated .If K_(f) for water is 1.86K Kgmol^(-1) ,w is

1Kg of an aqueous solution of Sucrose is cooled and maintained at -4^(@)"C". How much ice will be seperated out if the molality of the solution is 0.75? "K"_("F")("H"_(2)"O")=1.86"Kg mol"^(-1)"K"

124g of ethylene glycol (mol.Mass =62 ) was added to 935g of water. The solution was cooled upto -4^(@)C . How many gram of ice would be separated in the process? K_(f) of H_(2)O=1.86Kkgmol^(-1)

How many moles of sucrose should be dissolved in 500 g of water so as to get a solution which has a difference of 103.57^(@)C between boiling point and freezing point :- (K_(f)=1.86" K kg mol"^(-1), K_(b)="0.52 K kg mol"^(-1))

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