Home
Class 12
PHYSICS
An object is moving in a straight line. ...

An object is moving in a straight line. Its position versus time graph is shown below. There is a detector at origin which analyze the motion of object between `t=6` and `t=8` seconds, which statement describes the motion shown in the graph.

A

detector observes the object to be moving towards origin.

B

detector observes the object to be moving away from origin.

C

Detector observes the motion at decreasing speed.

D

Detector observes the motion at increasting speed.

Text Solution

Verified by Experts

The correct Answer is:
A

From `t=6 sec` to `t=8 sec`. Velocity of partcle is towards `-ve` `x-` axis and position is positive so object is moving towards origin.
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

An object starts at the origin in a straight line. Its velocity versus time graph is shown in the figure. Which one of the following choices best gives the proper intervals (s) of time for which the object is moving away from the origin?

Position (x) versus time (t) graph of a particle is as shown. The velocity is zero at?

A particle is moving in a straight line whose acceleration versus time graph is given. Assume that initial velocity is in the direction of acceleration. Then which of the statement is correct between time t =0 to t = t_(0) . .

For a particle moving in a straight line, the position-time graph is as shown in the figure. Find the velocity of the particle at time t=1 s and t=4 s . Also sketch the v-t graph.

The velocity-time graph of an object is shown below. The acceleration of the object is

In the given x - t graph. Find the position of an object at t = 3 second

Position (x) versus time (t) graph of a particle is as shown. The velocity is zero at (second)

Car A and car B move on a straight road and their velocity versus time graph are as shown in figure. Comparing the motion or car A in between t=0 to t =8 sec . And motion of car B in between t=0 to t=7 sec ., pick up the correct statement. .

The velocity-time graph of a linear motion is shown below. The distance from the origin after 8 seconds is :