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The enthalpy change for the following pr...

The enthalpy change for the following process are listed below`:`
`(a)` `Cl_(2(g)) rarr 2Cl_((g)), DeltaH=242.3kJ mol^(-1)`
`(b)` `I_(2(g))rarr 2I_((g)), DeltaH=151.0kJ mol^(-1)`
`(c)` `ICl_((g)) rarr I_((g))+Cl_((g)), DeltaH=211.3kJ mol^(-1)`
`(d)` `I_(2(s)) rarr I_(2(g)), DeltaH=62.76kJ mol^(-1)`
If standard state of iodine and chloride are `I_(2(s))` and `Cl_(2(g))` , the standard enthalpy of formation for `ICl_((g))` is `:`

A

`-14.6(KJ)/(mol)`

B

`-16.8(KJ)/(mol)`

C

`+16.8(KJ)/(mol)`

D

`+244.8(KJ)/(mol)`

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The correct Answer is:
C

`N//A`
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The enthalpy changes for the following process are listed below : Cl_(2)(g)=2Cl(g)," "242.3" kJ"mol^(-1) I_(2)(g)=2I(g)," "151.0" kJ"mol^(-1) ICl(g)=2I(g)+Cl(g)," "211.3" kJ"mol^(-1) I_(2)(s)=I_(2)(g)," "62.76" kJ"mol^(-1) Given that standard states for iodine and chlorine are I_(2)(s) and Cl_(2)(g) , the standerd enthalpy of formation for ICl(g) is :

The enthaplpy changes state for the following processes are listed below: Cl_(2)(g)=2Cl(g) : 242.3KJmol^(-1) I_(2)(g)=2I(g) , 151.0KJ mol^(-1) ICl(g)=I(g)+Cl(g) : 211.3KJ mol^(-1) I_(2)(s)=l_(2)(g) , 62.76KJ mol^(-1) Given that the standard states for iodine chlorine are I_(2)(s) and Cl_(2)(g) , the standard enthalpy of formation for ICl(g) is:

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