A block of mass `2kg` is pushed down an inclined plane of angle `37^(@)` above horizontal with a force parallel to inclined plane. The coefficient of friction is (3)/(4). The block moves `10 m` in `2` seconds starting form rest. The magnitude of the force is

Options

A. `10 N`
B. `12 N`
C. `24 N`
D. `34 N`

Answer

A

Explanation

FBD of block
Here `mgsintheta=f_(k)` so `a=(F)/(m)` but `a=5 m//s^(2)`,
hence `F=10N`