Water is flowing in a river at `2 ms^(-1)`. The river is `50 m` wide and has an average depth of `5 m`. The power available from the current in the river is (Density of water `= 1000 kg m^(3)`

Options

A. `0.5 MW`
B. `1 MW`
C. `1.5 MW`
D. `2 MW`

Answer

B

Explanation

`P=(1/2mv^(2))/t=(1)/(2)(m/t)v^(2)=(1)/(2)(rhoAv)v^(2)`
`=(1)/(2)rhoAv^(3)=(1)/(2)xx10^(3)xx50xx5xx(2)^(3)=10^(6)W`
`=1MW`