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In the arrangement shown in figure coeff...

In the arrangement shown in figure coefficient of friction between `5kg` block and incline plane is `mu=0.5`. Friction force acting on the `5kg` block is

A

`20 N`

B

`15N`

C

`10 N`

D

`5 N`

Text Solution

Verified by Experts

The correct Answer is:
C
`f_(min)=mumgcos37^(@)`
`20N`
But `2g+f=5gsin37^(@)`
`rArrf=10N`
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