Two bodies of masses `m_(1)` and `m_(2)` are acted upon by a constant force `F` for a time `t` . They start from rest and acquire kinetic energies `K_(1)` and `K_(2)` respectively. Then `(K_(1))/(K_(2))` is `:`

Options

A. `m_(1)/m_(2)`
B. `m_(2)/m_(1)`
C. `1`
D. `sqrt(m_(1)m_(2))/(m_(1)+m_(2))`

Answer

B

Explanation

`K=(1)/(2)mv^(2)=(1)/(2)m(at)^(2)=(1)/(2)m((Ft)/m)^(2)rArrKprop(1)/(m)`