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A partical of mass 2kg is moving on the ...

A partical of mass `2kg` is moving on the `x-`axis with a constant mechanical energy `20 J`. Its potential energy at any `x` is `U=(16-x^(2))J` where `x` is in metre. The minimum velocity of particle is `:-`

A

`2m//s`

B

`4m//s`

C

`6m//s`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A
From expression of potential energy Maximum
`PE=16J` so minimum `KE=4J`
Therefore `(1)/(2)xx2xxv^(2)=4rArrv=2m//s`
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