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A neutral atom (A) is converted to (A) b...

A neutral atom `(A)` is converted to `(A)` by the following process
`Aoverset(E_(1))underset(-e^(-1))rarrA^(+)overset(E_(2))underset(e^(-))rarrA^(+2)overset(E_(3))underset(e^(-))rarrA^(3+)`
The correct order of of `E_(1)`, `E_(2)` and `E_(3)` energies is `:-`

A

`E_(1)ltE_(2)ltE_(3)`

B

`E_(1)gtE_(2)gtE_(3)`

C

`E_(1)=E_(2)=E_(3)`

D

`E_(1)gtE_(2)ltE_(3)`

Text Solution

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The correct Answer is:
A
`N//A`
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