In ancient time, deffernt system of units was following in which unit of mass was "`ser`", unit of length was "`gaj`" & unit of time was "`kall`" `1ser=900 gm`, `1gaj=90cm`, `1 kaal=3hr`. A ball of mass `9kg` is moving with velocity `10 m//s`. Then its momentum (`mv`) in ancient system will be `:-`

Options

A. `1.2xx10^(6)` ser `gaj^(-1)`
B. `(10)^(-6)/(1.2)` ser gaj `"Kaal"^(-1)`
C. `1.2xx10^(6)` ser gaj `kaal^(-1)`
D. `120` ser gaj `kaal^(-1)`

Answer

C

Explanation

`n_(1)u_(1)=n_(2)u_(2)`
`rArr90(kg ms^(-1))=x(ser gaj kaal^(-1))`
`rArrx=90((kg)/(0.9kg)xx(m)/(0.9m)xx(3xx3600s)/(s))=1.2xx10^(6)`