A particle of mass `4 m` which is at rest explodes into masses `m, m` & `2m`. Two of the fragments of masses m and `2m` are found to move with equal speeds v each in opposite directions. The total mechanical energy released in the process of explosion is :-

Options

A. `mv^(2)`
B. `2mv^(2)`
C. `(1)/(2)mv^(2)`
D. `4mv^(2)`

Answer

B

Explanation

Ans.(2)

From momentum conservation velocity of third particle `=v`
Total `M.E.=2xx(1)/(2)mv^(2)+(1)/(2)mv^(2)=2mv^(2)`