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A box with weight 10N rests on a horizon...

A box with weight `10N` rests on a horizontal surface. A person pulls horizontally it with a force of `3N` and it does not move. To start its motion, a second person pulls it vertically upward. If `mu_(s)=0.5` and `mu_(k)=0.3`, then find the smallest vertical force for which the box starts moving.

A

`0N`

B

`4N`

C

`10N`

D

`6N`

Text Solution

Verified by Experts

The correct Answer is:
B
To start motion `3=mu_(x)(10-F)`
`rArr3=0.5(10-F)rArr6=10-FrArrF=4N`
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