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A man M slides down a curved frictionles...

A man `M` slides down a curved frictionless track, starting from rest.
The curve obeye the equation `y=(x^(2))/(2)`. The tangential acceleration of man is

A

`g`

B

`(gx)/(sqrt(x^(2)+4`

C

`(g)/(2)`

D

`(gx)/(sqrt(x^(2)+1`

Text Solution

Verified by Experts

The correct Answer is:
D
`(dv)/(dx)=tantheta=x`
tangential acceleration `=gsintheta`
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