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A parabola has its vertex and focus in t...

A parabola has its vertex and focus in the first quadrant and axis along the line `y=x` . If the distances of the vertex and focus from the origin are respectively `sqrt(2)&2sqrt(2)` , then equation of the parabola is `x^2+y^2-8x+8y+2x y=16` `x^2+y^2-8x-8y+16=2x y` `(x-y)^2=8(x+y-2)` `(x+y)^2=(x-y+2)`

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