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SO(2)Cl(2) is dissolved in water to obt...

`SO_(2)Cl_(2)` is dissolved in water to obtain `H_(2)SO_(4)` and HCL. In two different cases, excess `Ba(OH)_(2)` and excess `CH_(3)COOAg` were added to obtain precipitates having masses `m_(1)` and `m_(2)` grams respectively , starting with one mole of `SO_(2)Cl_(2)` in each case. Then (`Ba=137, Ag=108, S=32, Cl=35.5)`:-`

A

`m_(1)=233g`

B

`m_(2)-m_(1)=54g`

C

`m_(2)=287g`

D

All of these

Text Solution

Verified by Experts

The correct Answer is:
D
`SO-(2)Cl_(2)+2H_(2)Orarr`

`m_(1)=1molxx233g//mol=233g`
`m_(2)=2molxx143.5g//mol=287g`
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