Home
Class 11
PHYSICS
Position vector vec(r) of a particle var...

Position vector `vec(r)` of a particle varies with time t accordin to the law `vec(r)=(1/2 t^(2))hat(i)-(4/3t^(1.5))hat(j)+(2t)hat(k)`, where r is in meters and t is in seconds.
(a) Find suitable expression for its velocity and acceleration as function of time (b) Find magnitude of its displacement and distance traveled in the time interval `t=0` to `4 s`.

Text Solution

AI Generated Solution

To solve the problem step by step, we will break it down into parts (a) and (b) as per the question. ### Part (a): Finding Velocity and Acceleration 1. **Given Position Vector**: The position vector of the particle is given by: \[ \vec{r}(t) = \frac{1}{2} t^2 \hat{i} - \frac{4}{3} t^{1.5} \hat{j} + 2t \hat{k} ...
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS

    ALLEN|Exercise EXERCISE-01|55 Videos
  • KINEMATICS

    ALLEN|Exercise EXERCISE-02|57 Videos
  • ERROR AND MEASUREMENT

    ALLEN|Exercise Part-2(Exercise-2)(B)|22 Videos
  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN|Exercise BEGINNER S BOX-7|8 Videos

Similar Questions

Explore conceptually related problems

Position vector of a particle is expressed as function of time by equation vec(r)=2t^(2)+(3t-1) hat(j) +5hat(k) . Where r is in meters and t is in seconds.

The position vector of a particle changes with time according to the relation vec(r ) (t) = 15 t^(2) hat(i) + (4 - 20 t^(2)) hat(j) What is the magnitude of the acceleration at t = 1?

Find the Cartesian form the equation of the plane vec r=(s-2t)hat i+(3-t)hat j+(2s+t)hat k

A particle is moving along the x-axis such that s=6t-t^(2) , where s in meters and t is in second. Find the displacement and distance traveled by the particle during time interval t=0 to t=5 s .

The acceleration of particle varies with time as shown. (a) Find an expression for velocity in terms of t. (b) Calculate the displacement of the particle in the interval from t = 2 s to t = 4 s. Assume that v = 0 at t = 0.

The displacement of a particla moving in straight line is given by s=t^(4)+2t^(3)+3t^(2)+4 , where s is in meters and t is in seconds. Find the (a) velocity at t=1 s , (b) acceleration at t=2 s , (c ) average velocity during time interval t=0 to t=2 s and (d) average acceleration during time interval t=0 to t=1 s .

A particle moves along the space curve vec(r)=(t^(2)+t)hat(i)+(3t-2)hat(j)+(2t^(3)-4t^(2))hat(k) . (t in sec, r in m ) Find at time t=2 the (a) velocity, (b) acceleration, (c) speed or magnitude of velocity and (d) magnitude of acceleration.

The position vector vec(r) of a moving particle at time t after the start of the motion is given by vec(r) = (5+20t)hat(i) + (95 + 10t - 5 t^(2)) hat(j) . At the t = T, the particle is moving at right angles to its initial direction of motion. Find the value of T and the distance of the particle from its initial position at this time.

Velocity of a particle moving in a curvilinear path varies with time as v=(2t hat(i)+t^(2) hat(k))m//s . Here t is in second. At t=1 s

The position vector of a particle moving in x-y plane is given by vec(r)=(t^(2)-4)hat(i)+(t-4)hat(j) . Find (a) Equation of trajectory of the particle (b)Time when it crosses x-axis and y-axis