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A body is thrown up with a speed 49 m//s...

A body is thrown up with a speed `49 m//s`. It travels 5m in the last second of its upward journey. If the same body is thrown up with a velocity `98 m//s`, how much distance (in m) will it travel in the last second. `(g=10 m//s^(2))`

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The correct Answer is:
5
In last second of upward journey, all bodies travel same distance `(=g//2=5m)`
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