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A boy playing on the roof of a 10 m high...

A boy playing on the roof of a `10 m` high building throws a ball with a speed of `10 m//s` at an angle of `30^@` with the horizontal. How far from the throwing point will the ball be at the height of `10 m` from the ground ?
`[ g = 10m//s^(2) , sin 30^(@) = (1)/(2) , cos 30^(@) = (sqrt(3))/(2)]`

A

5.20 m

B

4.33 m

C

2.60 m

D

8.66 m

Text Solution

Verified by Experts

The correct Answer is:
4
`R=(u^(2) sin 2theta)/g`
`R=((10)^(2) sin 60^(@))/10`
`R=10xxsqrt(3)/2=5sqrt(3)=8.66 m`
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