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A projectile can have the same range 'R'...

A projectile can have the same range 'R' for two angles of projection . If `'T_(1)'` and `'T_(2)'` to be times of flights in the two cases, then the product of the two times of flights is directly proportional to .

A

`R^(2)`

B

`1/R^(2)`

C

`1/R`

D

`R`

Text Solution

Verified by Experts

The correct Answer is:
D
When a body is projected at an angles `theta` and `90-theta`, the ranges for both angles are equal and the corresponding time of flights for the two ranges are `t_(1)` and `t_(2)`.
`R=(2u^(2) sin theta cos theta)/g=1/2g((2u sin theta)/g)((2u sin (90^(@)-theta))/g)`
`=1/2 g t_(1)t_(2)rArr R propt_(1)t_(2)`
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