Home
Class 11
PHYSICS
A projectile is given an initial velocit...

A projectile is given an initial velocity of ` ( hat(i) + 2 hat (j) ) m//s`, where ` hat(i)` is along the ground and `hat (j)` is along the vertical . If ` g = 10 m//s^(2) `, the equation of its trajectory is :

A

`y=x-5x^(2)`

B

`y=2x-5x^(2)`

C

`4y=2x-5x^(2)`

D

`4y=2x-25x^(2)`

Text Solution

Verified by Experts

The correct Answer is:
2
`u=sqrt(5)` and `tan theta=2`
so by `y=x tan theta-(gx^(2))/(2u^(2))(1+tan^(2) theta)`
`rArr y=2x-(10x^(2))/(2xx5) (1+4)rArr y=2x-5x^(2)`
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS

    ALLEN|Exercise Exercise-05[B]|5 Videos

  • KINEMATICS

    ALLEN|Exercise MCQ with one or more than one correct Question|1 Videos

  • KINEMATICS

    ALLEN|Exercise Exercise-04[B]|14 Videos

  • ERROR AND MEASUREMENT

    ALLEN|Exercise Part-2(Exercise-2)(B)|22 Videos

  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN|Exercise BEGINNER S BOX-7|8 Videos

Similar Questions

Explore conceptually related problems

A projectile is given an initial velocity of (ˆi+2ˆj) m/s ,where hat i is along the ground and hat jis along the vertical.If g=10m/s^(2) ,the equation of its trajectory is

" A projectile is given an initial velocity "hat i+2hat j" .The cartesian equation of its path is "[" take "g=10m/s^(2)]

A projectile is given an initial velocity of (hat(i)+2hat(j)) The Cartesian equation of its path is (g = 10 ms^(-1)) ( Here , hati is the unit vector along horizontal and hatj is unit vector vertically upwards)

A particle has an initial velocity of 3hat(i) + 4 hat(j) and an acceleration of 0.4 hat(i) + 0.3 hat(j) . Its speed after 10s is :

A particle has an initial velocity of 4hat(i)+4hat(j) m//s and an acceleration of -0.4 hat(i) m//s^(2) at what time will its speed be 5 m//s?

A particle has an initial velocity (2 hat(i) + 3 hat(j)) and an accelaration (0.3 hat(i) + 0.2 hat(j)) . The magnitude of velocity after 10 s will be

A projectile is projected in air with initial velocity vec v=(3 hat i + 4 hat j) m/s from the origin. The equation of trajectory of the projectile is given as (g=-10 hat j m/s^2) (neglect air resistance )

A particle has initial velocity of (3hat(i)+4hat(j)) m//s and a acceleration of (4hat(i)-3hat(j)) m//s^(2) . Its speed after one second will be equal to :-

The unit vector along hat(i)+hat(j) is

A particle starts with an initial veloctiy (hat(i) + hat(j)) m//s and changes it to (3 hat(i) - 5 hat(j)) m//s in 2 sec. What is the magnitude of displacement of the particle in 2s, if the acceleration is constant ?