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From a tower of height H, a particle is ...

From a tower of height `H`, a particle is thrown vertically upwards with a speed `u` . The time taken by the particle , to hit the ground , is ` n` times that taken by it to reach the highest point of its path. The relative between ` H, u and n` is :

A

`2gH=nu^(2)(n-2)`

B

`gH=(n-2)u^(2)`

C

`2gH=n^(2)u^(2)`

D

`g H=(n-2)^(2)u^(2)`

Text Solution

Verified by Experts

The correct Answer is:
1
Time to reach highest point `=t=u/g`
time to reach ground`=nt`
`S=ut+1/2 at^(2)`
`-H=u(nt)-1/2 g(nt)^(2)`
`rArr 2gH=nu^(2)(n-2)`
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