Home
Class 12
PHYSICS
The plates of a parallel plate capacitor...

The plates of a parallel plate capacitor are separated by a distance `d = 1 cm`. Two parallel sided dielectric slabs of thickness `0. 7cm` and `0.3cm` fill the space between the plates. If the dielectric constants of the two slabs are 3 and 5 respectively and a potential difference of `440V` is applied across the plates. Find (a) The electric field intensities in each of the slabs. (b) The ratio of electric energies stored in the first to that in the second dielectric slab.

Promotional Banner

Similar Questions

Explore conceptually related problems

- The plates of a parallel plate capacitor are separated by 1cm .Two parallel sided dielectric slabs of thickness 0.6cm and 0.4cm fill the space between the plates.The dielectric constants of the two slabs are 3 and 5 respectively and a potential difference of 210V is applied across the plates.Electric field in the slab of 0.6cm thick is (k)/(-)times10^(4) V/m .The value of 'k is

The plates of a parallel plate capacitor are separated by 1cm .Two parallel sided dielectric slabs of thickness 0.6cm and 0.4 cm fill the space between the plates.The dielectric constants of the two slabs are 3 and 5 respectively and a potential difference of 210V is applied across the plates.Electric field in the slab of 0.6cm thick is (k)/(2)times10^(4)V/m .The value of k is

Capacitance of a parallel plate capacitor becomes 4//3 times its original value if a dielectric slab of thickness t=d/2 is inserted between the plates [d is the separation between the plates]. The dielectric constant of the slab is

The plates in a parallel plates capacitor are seperated by a distance d with air as the medium between the plates. In order to increase the capacity by 66% a dielectric slab of thickness (3d)/5 is introduced between the plates. What is the dielectric constant of the dielectric slab ?

The capacitance of a capacitor becomes 4//3 times its original value if a dielectric slab of thickness t=d//2 is inserted between the plates (d is the separation between the plates). What is the dielectric constant of the slab?

The separation between the plates of a parallel plate capacitor is d and the area of each plate is A. iff a dielectric slab of thickness x and dielectric constant K is introduced between the plates, then the capacitance will be

Derive a relation for the capacitance of a parallel plate capacitor having plate separation d, when a dielectric slab of thickness t is placed between the plates.

derive expression for capacitance of a parallel plate capacitor having dielectric slab of thickness .t. introduced between the plates of the capacitor.