Home
Class 12
PHYSICS
The isotope .(92)U^(238) successively un...

The isotope `._(92)U^(238)` successively undergoes eight `alpha`-decays and six `beta`-decays. The resulting isotope is found to be `._(92-5y)X^(238-4x)`. Find the value of ratio `x//y`.

Promotional Banner

Similar Questions

Explore conceptually related problems

If ._92 U^238 undergoes successively 8 alpha- decays and 6 beta- decays, then resulting nucleus is.

If ._92 U^238 undergoes successively 8 alpha- decays and 6 beta- decays, then resulting nucleus is.

A ._(92)^(238)Th undergoes alpha decay. What is the resulting daughter nucleus?

A ._(92)^(238)U undergoes alpha decay. What is the resulting daughter nucleus?

The nucleus resulting from ""_(92)U^(238) after successive emission of two alpha and four beta -particles is

""_(92)^(238)U under alpha -decay . The daughter nuclide belongs to group

The half - life of ._(92)U^(238) against alpha - decay is 4.5 xx 10^(9) years. How many disintegrations per second occur in 1 g of ._(92)U^(238) ?