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If x> 0, then the expression x^100/(1 + ...

If x> 0, then the expression `x^100/(1 + x + x^2 + x^3 .....x^200)` is always less than or equal to

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`AM>=GM`
`(1+x+x^2+x^3+x^4...X^200)/201>=(11*x^2*x^3...x^200)^(1/201)`
`1/201>=(x^((200+201)/2))^(1/201)/(1+x+x^2+...+x^200)`
`1/201>=x^100/(1+x+x^2+...+x^200)`
option 1 is correct.
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