If x and y are connected parametrically by the equations given, without eliminating the parameter, Find `(dy)/(dx)`.`x=a(theta-sintheta), y=a(1+costheta)`

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=a(theta-sin theta),y=a(1+cos theta)

If x and y are connected parametrically by the equations, without eliminating the parameter, Find (dy)/(dx) . x= a(theta-sin theta), y= a (1+ cos theta) .

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=a(costheta+thetasintheta), y=a(sintheta-thetacostheta)

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=4t,y=(4)/(t)

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=4t , y=4/t

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=asectheta, y=btantheta

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=acostheta, y=bcostheta

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=a sec theta,y=b tan theta

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=a cos theta,y=b cos theta

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=sin t,y=cos2t