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Two identical long metal wires having ra...

Two identical long metal wires having radius a are held parallel to each other at a separation `d (gt gt a)`. Calculate the capacitance of the system per unit length.

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The figure shows two identical long straight metal wires, A and B placed parallel to z-axis the cross sectional radius of each wire is R and the separation of the two wires is Dgt gtR . The electric potential at a perpendicular distance rgtR from a long straight wire due to that wire is given by V=-kln((r)/(R)) where k is a positive constant. the wires carry charges +Q and -Q per unit length respectively. Then Q. As D gt gt R , the electric field due to a long straight wire has cylindrical symmetry. The charge per unit length of the wire is

The figure shows two identical long straight metal wires, A and B placed parallel to z-axis the cross sectional radius of each wire is R and the separation of the two wires is Dgt gtR . The electric potential at a perpendicular distance rgtR from a long straight wire due to that wire is given by V=-kln((r)/(R)) where k is a positive constant. the wires carry charges +Q and -Q per unit length respectively. Then Q. As D gt gt R , the electric field due to a long straight wire has cylindrical symmetry. The charge per unit length of the wire is

The figure shows two identical long straight metal wires, A and B placed parallel to z-axis the cross sectional radius of each wire is R and the separation of the two wires is Dgt gtR . The electric potential at a perpendicular distance rgtR from a long straight wire due to that wire is given by V=-kln((r)/(R)) where k is a positive constant. the wires carry charges +Q and -Q per unit length respectively. Then Q. Consider a point P on the x-axis. The electric field at P is given by:

The figure shows two identical long straight metal wires, A and B placed parallel to z-axis the cross sectional radius of each wire is R and the separation of the two wires is Dgt gtR . The electric potential at a perpendicular distance rgtR from a long straight wire due to that wire is given by V=-kln((r)/(R)) where k is a positive constant. the wires carry charges +Q and -Q per unit length respectively. Then Q. Consider a point P on the x-axis. The electric field at P is given by: