Three distinct A.P.'s have same first term, common differences as `d_1,d_2,d_3 and n^(th)` terms as `a_n,b_n,c_n`respectively such that `a_1/b_1=(2b_1)/d_2=(3c_1)/d_3.` If `a_7/c_6=3/7` then `b_7/c_6` is equal to

Three distinct A.P. s' have same first term common differences as d_(1) ,d_(2) ,d_(3) and n^(th) terms as a_(n) , b_(n) ,c_(n) respectively such that (a_(1))/(d_(1))=(2b_(1))/(d_(2))=(3c_(1))/(d_(3)). If (a_(7))/(c_(6))=(3)/(7) then find the value of (b_(7))/(c_(6)) .

If a_n is the n^(th) term of an A.P whose first term is a and common difference is d, prove that n=(a_n-a)/d+1

If 6th , 7th , 8th, and 9th terms of (x+ y)^n are a,b,c and d respectively , then prove that : (b^2 - ac)/(c^2 -bd) =4/3. a/c

If 6th, 7th, 8th and 9th terms of (x+y)^n are a, b,c and d respectively, then prove that : (b^2-ac)/(c^2-bd)=4/3.a/c .

If the nth term of an AP is (3n+5) then its common difference is a)2 b)3 c)4 d)5

For the A.P. : 1/2,(-1)/2,(-3)/2,(-5)/2 ………, write the first term a and the common difference d. Find the 7^(th) term .

If the first and (2n + 1)th terms of an A.P. , G.P. and H.P. are equal and their (n + 1)th terms are a, b and c respectively, then

In the expansion of (x+P)^n ,the 6th ,7th,8th and 9th terms are a,b,c and d resp,show that (b^2-ac)/(c^2-bd)=(4a)/(3c)

If the sum of n terms of an A.P.be 3n^(2)-n and its common difference is 6, then its first term is 2 b.3 c.1 d.4