There positive numbers a b c in this order are said to form a pythagorean triplet if `c^2 = a^2 + b^2`

A triplet (mnp) of three natural numbers mn and p is called a pythagorean triplets if m^(2)+n^(2)=p^(2)

Assin different values to a and b and obtain Pythagorean triplets.

Three distinct numbers a, b, c form a GP in that order and the numbers a+b, b+c, c+a form an AP in that order. Then the common ratio of the GP is

Let a,b,c , d ar positive real number such that a/b ne c/d, then the roots of the equation: (a^(2) +b^(2)) x ^(2) +2x (ac+ bd) + (c^(2) +d^(2))=0 are :

For distinct positive numbers a,b and c, if a^2,b^2,c^2 are in A.P. Then which of the following triplets is also in A.P.

If a,b, and c are positive integers such that a+b+c le8 , the number of possible values of the ordered triplet (a,b,c) is

If a,b,c, are positive numbers such that 2a+3b+4c=9, then

The number a,b,c=60. that order form a term A.P and a+b+c=60. The number (a-2),b,(c+3) in that order form a three G.P.All possible values of (a^(2)+b^(2)+c^(2)) is/are

If positive numbers a, b, c are in H.P, then minimum value of (a+b)/(2a-b)+(c+b)/(2c-b) is