Area of rhombus `= 1/2` (Product of the diagonals)

Area of rhombus is 256 cm^2 . One of the diagonal is half of the other diagonal. The sum of the diagonals is :

The area of a rhombus if the lengths of whose diagonals are 16 cm and 24 cm, is

Area of a rhombus =1/2 product of ____________.

The symbolic form of "area (A) of a rhombus is half of the product of its diagonals (d_(1),d_(2)) " is_______.

Show that the area of a rhombus is half the product of the lengths of its diagonals.GIVEN : A rhombus ABCD whose diagonals AC and BD intersect at O. TO PROVE : ar (rhombus ABCD)=(1)/(2)(ACxBD)

Show that the area of a rhombus is half the product of the lengths of its diagonals.Given: A rhombus ABCD whose diagonals.AC and BD intersect at O. To Prove: ar (rhombus ABCD)=(1)/(2)(ACxBD)

The perimeter of a rhombus is 2pcm, the sum of its diagonals is mcm. Then area of rhombus is: