Arrange the following in correct order of their stability ? `(I) CH-=overset(Theta)C " "(II) CH_(2)=overset(Theta)CH " "(III) CH_(3)-overset(Theta)CH_(2)`

Arrange the following radicals in decreasing order of their stability. (I) overset(*)(C)H_(3) (II) CH_(3)-overset(*)(C )H_(2) (III)

Arrange the following anions in increasing order of stability and give reasons: CH_(2)=overset(Theta)(C)H,CH_(3)overset(Theta)(C)H_(2),CH-=overset(Theta)(C)

Arraange the follwooing carbanions in decreasing order of their stability : I. CH -= overset( -)(C ) II. CH_(3) - C -= overset( - ) ( C ) III. CH_(2) = overset(- )( C ) H IV. CH_(3) - overset( - )( C ) H_(2) The correct choice is :

Arraange the follwooing carbanions in decreasing order of their stability : I. CH -= overset( -)(C ) II. CH_(3) - C -= overset( - ) ( C ) III. CH_(2) = overset(- )( C ) H IV. CH_(3) - overset( - )( C ) H_(2) The correct choice is :

Basic strength of CH-=overset(Theta)C(l), CH_(2)=overset(Theta) CH(II) and CH_(3)overset(Theta)CH_(2)(III) will be in order

Decreasing order of stability of the given carbanions is (a) CH_3-C-=overset(Theta)C: (b) H-C-=overset(Theta)C: (c )CH_3-overset(Theta)overset(..)CH_2

Arrange the following in their nucleophilicity order. (I) C_(6)H_(5)O^(Theta) (II) C_(6)H_(5)S^(Theta) (III) C_(6)H_(5) - overset(Theta)CH_(2) (IV) CH_(3)-overset(O)overset(||)C-overset(Theta)CH_(2)

Write stability order of following intermediates: (a)HC -= overset(Theta)C" "(b) CH_(3) - overset(Theta)CH - CH_(3) (c) CH_(3) - C underset(CH_(3))underset(|)overset(CH_(3))overset(|)Theta