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A point object O is kept in front of a p...

A point object O is kept in front of a plane mirror AB having length L = 2 m. The line AOM makes an angle `theta = 60°` with the mirror. An observer is walking along the line XMX' (perpendicular to AOM). Find the length of his path along XMX' in which he can see the image of the object. Given `AO = d = 1 m` and `AM = 2d`.
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Text Solution

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The correct Answer is:
`(10)/(sqrt(3))m`
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