Solve the cryptarithm : `overline(AB)+overline(BA)=overline(DAD)`

Solve the cryptarithm :AB+BA=DAD

If ABCDEF is a regular hexagon inscribed in a circle with centre O, then overline(AB)+overline(AC)+overline(AD)+overline(AE)+overline(AF)=

overline(AB)-overline(CB)+overline(DA)+2overline(CD)=

ABCDE is a pentagon. The resultant of the vectors overline(AB), overline(AE), overline(BC), overline(DC), overline(ED) and overline(AC) in terms of overline(AC) is

If A, B, C, D, E are five coplanar points, then overline(DA)+overline(DB)+overline(DC)+overline(AE)+overline(BE)+overline(CE)=

If overline(a), overline(b), overline(c) be three vecotrs such that overline(a)timesoverline(b)=overline(c), overline(b)timesoverline(c)=overline(a), overline(c)timesoverline(a)=overline(b) , then

If ABCDE is a pentago, then overline(AB)+overline(BC)+overline(CD)+overline(DE)-overline(AE)=

If ABCD is a quadrilateral, then 2overline(AB)+3overline(BC)+2overline(CD)+overline(DA)+overline(CA)+overline(DB)=

If ABCDEF is a regular hexagon, then overline(AB)+overline(AC)+overline(AE)+overline(AF)=