Formula 3 Let P be the population of a city or a town at the beginning of a certain year. if the population decreases at the rate of `R%` per annum then population after n years `= P (1- R/100)^n

Formula 1 Let P be the population of a city or a town at the beginning of a certain year and the population grows at a constant rate of R% per annum then population after n years =P(1+(R)/(100))^(n)

Formula 2 Let P be the population of a city or a town at the beginning of a certain year.If the population grows at the rate of R_(1)% during first year and R_(2) during second year then population after 2 years =P(1+(R_(1))/(100))xx(1+(R_(2))/(100))

If the population P of a town increases at R% per annum, then its population after 5 years is …….

The present population of a city is 180000. If it increases at the rate of 10% per annum, its population after 2 years will be :

The present population of a city is 18000. If it increases at the rate of 10% per annum, its population after 2 years will be:

The present population of a town is 28000. If it increases at the rate of 5% per annum, what will be its population after 2 years?

The present population of a town is 24000. If if increases at the rate of 5% per annum, what will be its population after 2 years?

The population of a town is 125000. It is increasing at the rate of 2% per annum. What will be its population after 3 years?