N-sides of a convex polygons and `n> 3` then it has `(n(n-3))/2`diagonals.

Show that a convex polygon of m sides has (m(m-3))/2 diagonals

The number of diagonals of a convex polygon of sides n is equal to (n(n-3))/(2) . Find the number of diagonals is hexagon.

Remark 2 if there is a regular polygon of n sides (n >= 3) then its each interior angle is equal to ((2 n-4)/n)right angles i.e.((2 n-4)/(n)x 90).

Given that the angles of a polygon are all equal and each angle is a right angle. Statement-1 : The polygon has exactly four sides. Statement-2: The sum of the angles of a polygon having n sides is (3n - 8) right angles. Which one of the following is correct in respect of the above statements ?

Consider a convex polygon, which has 44 diagonals, then the number of triangles formed by joining the vertices of polygon in which exactly one side is common in triangle and polygon, is

A regular polygon of n sides has 170 diagonals.Then n=

Convex polygon a polygon p_(1)p_(2)p_(3)...p_(n) is called a convex polygon if for each side of the polygon the line containing that side has all the other vertices of the polygon on the same side of it.

Consider the following statements : 1. If n ge 3 and mge3 are distinct positive integers, then the sum of the exterior angles of a regular polygon of m sides is different from the sum of the exterior angles of a regular polygon of n sides. 2. Let m, n be integers such that m gt n ge 3 . Then the sum of the interior angles of a regular polygon of m sides is greater than the sum of the interior angles of a regular polygon of n sides, and their sum is (m+n)(pi)/(2) . Which of the above statements is/are correct?