If `a+b+c!=0,` the system of equations `(b+c)(y+z)-ax=b-c, (c+a)(z+x)-by=c-a` and `(a+b)(x+y)-cz=a-b` has

If a+b +c ne 0 , the system of equations (b+c) (y+z)-ax=b-c , (c+a) (z+x)-by=c-a , (a+b)(x+y)-cz=a-b has

If a + b + c != 0 then the number solutions (x,y,z) to the system (b + c)(y + z) - ax = b - c (c + a)(z + x) - by = c - a (a + b) (x + y) - cz = a - b is

Solve the following systems of equations by Cramer's Rule: (b+c) (y+z) -ax=b-c,(C+a)(z+x) -by = c-a,(a+b)(x+y)-cz=a-b

If (b + c) (y + z) - ax = b - c, (c + a) (z + x) - by = c - a and (a + b) (x + y) - cz = a - b , where a + b + c ne 0, then x is equal to a) (c + b)/(a + b + c) b) (c - b)/(a + b + c) c) (a - b)/(a + b + c) d) (a + b)/(a + b + c)

If the system of equations ax + by + c = 0,bx + cy +a = 0, cx + ay + b = 0 has infinitely many solutions then the system of equations (b + c) x +(c + a)y + (a + b) z = 0(c + a) x + (a+b) y + (b + c) z = 0(a + b) x + (b + c) y +(c + a) z = 0 has

If the system of equations ax + by + c = 0,bx + cy +a = 0, cx + ay + b = 0 has infinitely many solutions then the system of equations (b + c) x +(c + a)y + (a + b) z = 0 (c + a) x + (a+b) y + (b + c) z = 0 (a + b) x + (b + c) y +(c + a) z = 0 has

The product of all values of t , for which the system of equations (a-t)x+b y+c z=0,b x+(c-t)y+a z=0,c x+a y+(b-t)z=0 has non-trivial solution, is (a) |[a, -c, -b], [-c, b, -a], [-b, -a, c]| (b) |[a, b, c], [b, c, a], [c, a, b]| (c) |[a, c, b], [b, a, c], [c, b, a]| (d) |[a, a+b, b+c], [b, b+c, c+a], [c, c+a, a+b]|