Find the largest number that divides 2053 and 967 and leaves a remainder of 5 and 7 respectively.

Explanation

let the number be x.

Now if it leaves a remainder 5 when 2053 is divided by it then 2048(2053-5) is divisible by it.

similarly 960 (967-7) is also divisible by it.

HCF of 2048 and 960=64.

answer:64.