if `I = int_(-3) ^2 (|x+1|+|x+2|+|x-1|)dx`

int_(1)^(3)(|x-1|)/(|x-2|+|x-3|)dx=

Evaluate: int_(0)^(1)|5x-3|dx( ii) int_(0)^( pi)|cos x|dx( iii) int_(-5)^(5)|x-2|dx( iv )int_(-1)^(1)e^(|x|)dx(v)int_(0)^(2)|x^(2)+2x-3|dx(v)int_(1)^(4)(|x-1|+|x-2|+|x-3|)dx( vi) int_(1)^(2)|x^(3)-x|dx

If I_(1)=int_(1-x)^(x) x sin{x(1-x)}dx and I_(2)=int_(1-x)^(x) sin{x(1-x)}dx , then

I = int( 6 x^(3) + x^(2)-2x + 1) /( 2x - 1) dx .

If I_(1) = int_(0)^(1) 2^(x^(2))dx, I_(2) = int_(0)^(1) 2^(x^(3))dx , I_(3) = int_(1)^(2) 2^(x^(2))dx, I_(4)=int_(1)^(2) 2^(x^(3))dx then

If I_(1) = int_0^(1) 2^(x^(2)) dx, I_(2) = int_0^(1) 2^(x^(3)) dx, I_(3) = int_1^(2) 2^(x^(2)) dx, I_(4) = int_1^(2) 2^(x^(3)) dx then,

Let I=int_(1)^(3)|(x-1)(x-2)(x-3)|dx The value of I^(-1) .

Let I=int_(1)^(3)|(x-1)(x-2)(x-3)|dx. The value of I^(-1) .