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In rhombus ABCD, show that 4AB^2 = AC^2...

In rhombus ABCD, show that `4AB^2 = AC^2+BD^2`

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For a rhambus ABCD , prove that 4 AB ^(2) = AC^(2) + BD^(2)

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In a rhombus ABCD, prove that AC^(2) + BD^(2) = 4AB^(2)

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Consider the following statements : 1. Let ABCD be a parallelogram which isnot a rectangle. Then (AB ^(2) + BC ^(2)) ne AC ^(2) + BD ^(2) 2. If ABCD is a rhombus with AB = 4 cm, then AC ^(2) + BD ^(2) = n ^(2) for some positive integer n. Which of the above statements is/are correct?