From a certain tower of unknown height it is found that the maximum range at a certain pfojection velocity velocity is obtained for a projection angle of `30^(@)` and this range is `10sqrt3 m`. The projection velocity must be

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. From a certain tower of unknown height it is found that the maximum range at a certain projection velocity is obtained for a projection angle of 30^(@) and this range is 10sqrt(3)m . The projection velocity must be

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. From a certain tower of unknown height it is found that the maximum range at a certain projection velocity is obtained for a projection angle of 30^(@) and this range is 10sqrt(3)m . The projection velocity must be

The velocity at the maximum height of a projectile is half of its velocity of projection u . Its range on the horizontal plane is

The velocity at the maximum height of a projectile is half of its velocity of projection u . Its range on the horizontal plane is

The velocity at the maximum height of a projectile is half of its velocity of projection u . Its range on the horizontal plane is

The range of a projectile for a given initial velocity is maximum when the angle of projection is 45^(@) . The range will be minimum, if the angle of projection is

The velocity at the maximum height of a projectile is sqrt(3)/2 times the initial velocity of projection. The angle of projection is

The velocity at the maximum height of a projectile is sqrt(3)/2 times the initial velocity of projection. The angle of projection is