The domain of the function `f(x)=1/(sqrt(|x|-x))` is: (1) `(-oo,oo)` (2) `(0,oo` (3) `(-oo,""0)` (4) `(-oo,oo)"-"{0}`

Similar Questions

Explore conceptually related problems

The domain of the function f(x)=1/(sqrt(|x|-x)) is: (A) (-oo,oo) (B) (0,oo (C) (-oo,""0) (D) (-oo,oo)"-"{0}

The range of the function f(x)=|x-1| is A. (-oo,0) B. [0,oo) C. (0,oo) D. R

The domain of definition of f(x)=x-3-2sqrt(x-4)-x-3+2sqrt(x-4) is [4,oo) b. (-oo,4] c. (4,oo) d. (-oo,4)

The interval of increase of the function f(x)=x-e^x+tan(2pi//7) is (a) (0,\ oo) (b) (-oo,\ 0) (c) (1,\ oo) (d) (-oo,\ 1)

The domain of f(x)=(1)/(sqrt((x-2)(7-x))) is )(2,oo)( ii) (7,oo)( iii) (2,7)( iv )(-oo,2)

The domain of definition of f(x)=x-3-2sqrt(x-4)-x-3+2sqrt(x-4) is a. [4,oo) b. (-oo,4] c. (4,oo) d. (-oo,4)

The interval of increase of the function f(x)=x-e^(x)+tan(2 pi/7) is (a) (0,oo)(b)(-oo,0)(c)(1,oo)(d)(-oo,1)

The set of points where the function f(x)=x|x| is differentiable is (-oo,oo) (b) (-oo,0)uu(0,oo) (0,oo) (d) [0,oo)

The domain of the function f(x) = sin ^(-1) ((|x| +5)/(x^2 +1)) is ( -oo , -a ] uu [ a,oo ). then a is equal to :