`(-5)/(13)+?=-1` `8/(13)` (b) `(-8)/(13)` `(-18)/(13)` (d) `(18)/(13)`

Simplify: 1/(1+(2/3)/(1+2/3+(8/9)/(1-2/3))) . (11)/(13) (b) (13)/(15) (c) (13)/(11) (d) (15)/(13)

(9)/(13)+(-8)/(13)+(4)/(3)+(-5)/(8)

Solve: (5)/(13) - (-8)/(26)

Re-arrange suitably and find the sum in each of the following: (3)/(5)+(7)/(3)+(9)/(5)+(-13)/(15)+(-7)/(3) (ii) (4)/(13)+(-5)/(8)+(-8)/(13)+(9)/(13)

Solve : ((-5)/(13) + ((-2))/( 13)) + ((- 3)/(8) + (18)/(20))

(-5)/8+(-9)/13=(-9)/13+(-5)/8

Two circles, each having radius 4, have a common tangent given by 3x+2y-6=0 at (2, 0) . Then their centres are : (A) (2+ 5/sqrt(13), 8/sqrt(13)), (2- 5/sqrt(13) , (-8)/sqrt(13)) (B) (2+ 12/sqrt(13), 8/sqrt(13)) , (2- 12/sqrt(13), (-8)/sqrt(13)) (C) (2, 3), (4, 5) (D) none of these

Two cards are drawn from a well shuffled deck of 52 playing cards with replacement. The probability that both cards are queen is 1/(13)xx1/(13) b. 1/(13)+1/(13) c. 1/(13)xx1/(17) d. 1/(13)xx4/5

Solve : 4/(13)+2/(13)+1/(13)

Simplify: (-8)/7xx(14)/5 (ii) (13)/6xx(-18)/(91)