Home
Class 7
MATHS
(-1)^(301)+(-1)^(302)+(-1)^(303)+ ....+(...

`(-1)^(301)+(-1)^(302)+(-1)^(303)+` ....`+(-1)^(400)` (b) 101 100 (d) 0

Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

Find the value of (-1)^(301)+(-1)^(302)+(-1)^(303)+.......+(-1)^(400) .

The simplified value of (1+(1)/(1+(1)/(100)))(1+(1)/(1+(1)/(100)))-(1-(1)/(1+(1)/(100)))(1-(1)/(1+(1)/(100))) (a) 100( b) (200)/(101) (c) 200 (d) (202)/(100)

The rational numbers lying between (1)/(3) and (3)/(4) are (117)/(300),(287)/(400) (b) (95)/(300),(301)/(400) (c) (99)/(300),(301)/(400) (d) (97)/(300),(299)/(500)

[(1+(1)/(10+(1)/(10)))(1+(1)/(10+(1)/(10)))-(1-(1)/(10+(1)/(10)))(1-(1)/(10+(1)/(10)))] simplifies to (20)/(101) (b) (90)/(101) (c) (100)/(101) (d) (101)/(100)

(25.025)/(0.025) is equal to (a) 1.01 (b) 10.1(c)101 (d) 1001

Let S_(n)=1+q+q^(2)+?+q^(n) and T_(n)=1+((q+1)/(2))+((q+1)/(2))^(2)+?+((q+1)/(2)) If alpha T_(100)=^(101)C_(1)+^(101)C_(2)xS_(1)+^(101)C_(101)xS_(100), then the value of alpha is equal to (A) 2^(99)(B)2^(101)(C)2^(100) (D) -2^(100)

If f(x)=prod_(n=1)^(100)(x-n)^(n(101-n)), where prod_(i=1)^(k)a_(i) stands for product a_(1)dot a_(2).........a_(k), then (f(101))/(f'(101))=(a)5050( b) (1)/(5050) (c) 10010 (d) (1)/(10010)

Let S_(1),S_(2),...,S_(101) be consecutive terms of an AP.If (1)/(S_(1)S_(2))+(1)/(S_(2)S_(3))+...+(1)/(S_(100)S_(101))=(1)/(6) and S_(1)S_(101)=50 then |S-S_(101)| is equal to

int_(0)^(102)(x-1)(x-2)dots(x-100)xx((1)/(x-1)+(1)/(x-2)+.(.1)/(x-100))dx=101!-100

RD SHARMA-EXPONENT-All Questions
  1. (3^(-1)xx5^(-1))^(-1)()(\ \ )= 1/(15)\ \ \ (b) -1/(15) 15 (d) -15

    Text Solution

    |

  2. (-3/5)^(-1) = 3/5 (b) 5/3 -5/3 (d) -3/5

    Text Solution

    |

  3. (-1)^(301)+(-1)^(302)+(-1)^(303)+ ....+(-1)^(400) (b) 101 100 (d) 0

    Text Solution

    |

  4. If a=25 , then a^((25)^0)+a^(0^(25))= (a)25 (b) 26 (c)24 (d) 0

    Text Solution

    |

  5. {(1/3)^(-3)-(1/2)^(-3)}-:(1/4)^(-3) = (19)/(64) (b) (64)/(19) (27)/(1...

    Text Solution

    |

  6. (25^2-15^2)^(3/2) = 4000\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ...

    Text Solution

    |

  7. If (5/3)^(-5)xx(5/3)^(11)=(5/3)^(8x) , than x=? (a)-1/2 (b) -3/4 (c)...

    Text Solution

    |

  8. [{(-1/3)^2}^(-2)]^(-1) = (a) 1/(81) (b) 1/9 (c) -1/(81) (d) -1/9

    Text Solution

    |

  9. ((144)^(1/2)+(256)^(1/2))/(3^2-2)= (A) 8 (B) 4 (C) -4 (D) -8

    Text Solution

    |

  10. ( 1+3+5+7+9+11 )^ (3/2)   = (a)36                              ...

    Text Solution

    |

  11. If a b c = 0, then ({(x^a)^b}^c)/({(x^b)^c}^a) = (a)3 (b) 0 (c)-1 (d...

    Text Solution

    |

  12. (2^3)^4 = 2^4^3 (b) 2^3^4 (2^4)^3 (d) none of these

    Text Solution

    |

  13. { ( 33 ) 2 − ( 31 ) 2 } 5 7 = (a)64               ...

    Text Solution

    |

  14. If a b c=0 , then find the value of {(x^a)^b}^c (a)1 (b) a (c)b (d) ...

    Text Solution

    |

  15. If a=3^(-3)-3^3\ a n d\ b=3^3-3^(-3),\ t h e n a/b-b/a (a) 0 (b) 1 (c)...

    Text Solution

    |

  16. What should be multiplied to 6^(-2) so that the product may be equal t...

    Text Solution

    |

  17. If x y z=0, then find the value of (a^x)^(y z)+(a^y)^(z x)+(a^z)^(x y)...

    Text Solution

    |

  18. If 2^n=4096 , t h e n\ 2^(n-5) = (a)128 (b) 64 (c)256 (d) 32

    Text Solution

    |

  19. The number 4, 70 , 394 is standard from is written as (a)4.70394xx10^5...

    Text Solution

    |

  20. The number 2.35xx10^4 in the usual from is written as (a)2. 35xx10^3 (...

    Text Solution

    |