Two waves are represented by the equations `y_1=a sin omega t` and `y_2=a cos omegat`. The first wave

Two wave are represented by equation y_(1) = a sin omega t and y_(2) = a cos omega t the first wave :-

Two coherent waves are represented by y_1=a_1 cos omega t and y_2=a_2 cos (pi/2 - omega t) . Their resultant intensity after interference will be-

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

Two harmonic travelling waves are described by the equations y_(1)=a sin(kx-omega t) and y_(2)=a sin(-kx+omega t+phi) . The amplitude of the superimposed wave is

The two waves represented by y_1=a sin (omegat) and y_2=b cos (omegat) have a phase difference of

Two light waves are represented by y_(1)=a sin_(omega)t and y_(2)= a sin(omega t+delta) . The phase of the resultant wave is

The resultant intensity after interference of two coherent waves represented by the equation Y_(1)=a_(1)sin omega t and Y_(2)=a_(2)sin((pi)/(2)-omega t) will be proportional to

Two waves represented as y_(1) = A_(1) sin omega t and y_(2) = A_(2) cos omega t superpose at a point in space. Find out the amplitude of the resultant wave at that point .