For steel `Y=2xx10^(11) Nm^(-2)`. The force required to double the length of a steel wire of area 1 `cm^(2)` is

If young's modulus of steel is 2xx10^(11)N//m^(2) , then the force required to increase the length of a wire of cross section 1 cm^(2) by 1% will be

Determine the force required to double the length of the steel wire of area of cross-section 5 xx 10^(-5) m^(2) . Give Y for steel = 2 xx 10^(11) Nm^(-2) .

The area of cross section of a steel wire (Y=2.0 xx 10^(11) N//m^(2)) is 0.1 cm^(2) . The force required to double is length will be

The area of cross section of a steel wire (Y=2.0xx10^11 N//m^2) is 0.1 cm^2 . The force required to double its length will be

The area of cross section of a steel wire (Y=2.0 xx 10^(11) N//m^(2)) is 0.1 cm^(2) . The force required to double is length will be

The area of cross section of a steel wire (Y=2.0 xx 10^(11) N//m^(2)) is 0.1 cm^(2) . The force required to double is length will be

The area of cross section of a steel wire (Y=2.0 xx 10^(11) N//m^(2)) is 0.1 cm^(2) . The force required to double is length will be

The area of a cross-section of steel wire is 0.1 cm^(-2) and Young's modulus of steel is 2 x 10^(11) N m^(-2) . The force required to stretch by 0.1% of its length is

The area of a cross-section of steel wire is 0.1 cm^(-2) and Young's modulus of steel is 2 x 10^(11) N m^(-2) . The force required to stretch by 0.1% of its length is